MATH SOLVE

5 months ago

Q:
# Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the value of the third quartile q3. round your answer to the nearest tenth.

Accepted Solution

A:

we need to find α=Q3 such that P(z≤α)=0.75

From the standard table, we get

P(Z≤0.675)=0.75

thus

α=0.675

⇒[H-63.6]/2.5=0.675

solving for H we get

H-63.6=1.6875

hence

H=65.2875

The 3rd quartile is 65.2875

From the standard table, we get

P(Z≤0.675)=0.75

thus

α=0.675

⇒[H-63.6]/2.5=0.675

solving for H we get

H-63.6=1.6875

hence

H=65.2875

The 3rd quartile is 65.2875