Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the value of the third quartile q3. round your answer to the nearest tenth.
Accepted Solution
A:
we need to find α=Q3 such that P(z≤α)=0.75 From the standard table, we get P(Z≤0.675)=0.75 thus α=0.675 ⇒[H-63.6]/2.5=0.675 solving for H we get H-63.6=1.6875 hence H=65.2875 The 3rd quartile is 65.2875