What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that apply. y = −Two-fifthsx − 1 2x + 5y = −5 y = −Two-fifthsx − 3 2x + 5y = −15 y − 1= −Two-fifths(x + 5)

Answer:2x + 5y = -5Step-by-step explanation:Since the new line is parallel to the given line 2x + 5y = 10, the equation of the new line has exactly the same form as does 2x + 5y = 10, except that the constant will be different.Were we to solve this equation (in standard form) for y in slope-intercept form, we'd get:5y = -2x + 10, or         -2x + 10y = ----------------               5or      y =  (-2/5)x + 2               Writing out 2x + 5y = C, we substitute -5 for x and 1 for y, obtaining2x + 5y = C  =>  2(-5) + 5(1) = -10 + 5 = -5.  Therefore, C = -5 and the equation of the new line is2x + 5y = -5